Lewis Structure of CH₂O (Formaldehyde)
What is the Lewis structure of CH₂O?
CH₂O has 12 valence electrons, 4 bonding electron pairs, and 2 lone pairs. Formaldehyde has 12 valence electrons. Two C–H single bonds use 4, the C=O double bond uses 4, and 2 lone pairs on oxygen use the remaining 4. All atoms have FC = 0.
| Formula | CH₂O |
| Name | Formaldehyde |
| Total Valence Electrons | 12 |
| Lone Pairs | 2 |
| Has Resonance | No |
| Concept | Multiple Bonds |
| Difficulty | Intermediate |
Step 1: Count Valence Electrons
C has 4, O has 6, each H has 1: 4 + 6 + 1 + 1 = 12 total.
Step 2: Draw the Skeleton
Carbon is central, bonded to two H’s and one O. Three single bonds use 6 electrons; 6 remain.
Step 3: Distribute Lone Pairs
Place 3 lone pairs on O (6 e⁻). But C only has 6 electrons — needs 8.
Step 4: Form Multiple Bonds
Convert 1 lone pair from O into a bonding pair: C–O → C=O. Carbon now has 8 electrons. Oxygen keeps 2 lone pairs + double bond = 8.
Step 5: Check Formal Charges
- C: FC = 4 - 0 - ½(8) = 0
- O: FC = 6 - 4 - ½(4) = 0
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